How to Calculate the Right System Size for 1,000 kWh/Month
The core formula has three steps. First, convert monthly usage to daily: 1,000 kWh ÷ 30 days = 33.3 kWh per day. Second, divide by your location’s average peak sun hours to get the required system output in kilowatts. Third, divide by individual panel wattage to get panel count.
Using the US average of 4.5 peak sun hours and accounting for a standard 80% system efficiency factor — covering inverter losses, wiring resistance, and temperature derating — the math looks like this:
Required system size = 33.3 kWh ÷ (4.5 h × 0.80) = 9.25 kW
At 400W per panel — the most common residential panel size in 2026 — that’s 9,250W ÷ 400W = 23–24 panels. Drop to 350W panels and you need 27. Step up to 440W premium panels and you need 21. The table below shows how panel wattage and location interact:
Panel Count by Location and Wattage (1,000 kWh/Month, 80% System Efficiency)
| Peak Sun Hours | 350W Panels | 400W Panels | 440W Panels |
|---|
| 3.5 hrs (Seattle, WA) | 34 | 30 | 27 |
| 4.0 hrs (Denver, CO) | 30 | 26 | 24 |
| 4.5 hrs (Dallas, TX) | 27 | 23 | 21 |
| 5.5 hrs (Phoenix, AZ) | 22 | 19 | 17 |
| 5.9 hrs (Miami, FL) | 20 | 18 | 16 |
When we modelled a 9.25 kW system in NREL’s PVWatts Calculator using ZIP code 78701 (Austin, TX — 4.9 peak sun hours), the tool returned an annual output of 13,840 kWh, or roughly 1,153 kWh per month — slightly above the 1,000 kWh target, which provides a useful buffer during cloudy months. Use our solar system size calculator to enter your ZIP code and get a location-specific panel count in under two minutes.
People often ask whether they need to size for their worst month or their annual average. The answer: size for the annual average and let net metering handle the seasonal imbalance. Summer surplus credits offset winter shortfalls in most states with full-retail net metering policies.