How to Calculate Solar Panels for a Weekend Cabin
Start with your daily energy use. List every appliance you will run on a typical day, multiply its wattage by the hours it runs, and add the results. That total is your daily load in watt-hours (Wh). Basic cabins often land near 1 kWh per day; cabins with a refrigerator, pump, and electronics can reach 3–4 kWh per day or more. For context, the U.S. Energy Information Administration reports that an average American home uses roughly 29 kWh per day, so even a well-equipped cabin is a fraction of that.
Next, find your site’s peak sun hours with the free NREL PVWatts calculator. One peak sun hour equals 1 kWh of sunlight per square meter, and annual averages in the contiguous US run from roughly 3.5 in cloudy northern areas to above 6 in the Southwest.
Then use this formula:
Array size (W) = daily Wh ÷ peak sun hours × 1.25
The 1.25 multiplier is a common planning allowance for wiring, charge controller, inverter, and battery losses, plus slow panel aging. NREL research on field data found median degradation of about 0.5% per year, so the allowance covers that comfortably. Divide the result by your panel’s wattage (most residential panels today are around 400 W) and round up.
Worked example: a cabin using 2,000 Wh per day at a site with 4.5 peak sun hours needs 2,000 ÷ 4.5 × 1.25 = 556 W. With 400 W panels, that rounds up to 2 panels. At 4,000 Wh per day, the same site needs about 1,111 W, or 3 panels.
Use our solar system size calculator to run your own numbers. For similar small-space builds, see our guides for a log cabin and a tiny house.